How do you factor the expression #7x^2 - 42x - 49#?

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Answer 1 · 2016-05-20T11:10:18

#(7x-49)(x+1)#

Divide each term by 7

#x^2-6x-7#

Factorise this equation

#(x-7)(x+1)#

Therefore #7(x-7)(x+1)#

= #(7x-49)(x+1)#

From this, you can then solve for #x#,

so #x=1# or #x=-1/7#