Question

How do you factor the expression `x^2 + 2/3x + 1/9`?

Answer 1

`(x+1/3)^2`

Explanation:

This is a perfect square trinomial, which take the form:

`(x+a)^2=a^2+2ax+a^2`

In

`x^2+2/3x+1/9`

We see that `a=1/3`, since `2a=2/3` and `a^2=1/9`.

`(x+1/3)^2=x^2+1/3x+1/3x+1/9=x^2+2/3x+1/9`