Question

How do you factor the expression `y^2 + 14xy + 49x^2`?

Answer 1

`y^2+14xy+49x^2=(y+7x)(y+7x)=(y+7x)^2`

Explanation:

This is a perfect square trinomial

`a^2+2ab+b^2=(a+b)(a+b)`

with `a=y` and `b=7x`

`y^2+14xy+49x^2=(y+7x)(y+7x)=(y+7x)^2`

God bless....I hope the explanation is useful.