How do you factor the expressions #w^3-2w^2-63w#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer ali ergin May 28, 2016 #omega^2-2omega^2-63 omega=omega(omega-9)(omega+7)# Explanation: #omega^2-2omega^2-63 omega=omega(omega^2-2omega-63)# #omega^2-2omega-63=(omega-9)(omega+7)# #omega^2-2omega^2-63 omega=omega(omega-9)(omega+7)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1082 views around the world You can reuse this answer Creative Commons License