How do you factor the expressions #x^2 - 16x + 63 = 0#?
1 Answer
Apr 23, 2016
Explanation:
In general:
#(x-a)(x-b) = x^2-(a+b)+ab#
We find
#x^2-16x+63 = (x-7)(x-9)#
In general:
#(x-a)(x-b) = x^2-(a+b)+ab#
We find
#x^2-16x+63 = (x-7)(x-9)#