How do you factor the trinomial 100x^3-40x^2+4x?
1 Answer
Apr 30, 2016
Explanation:
All of the terms are divisible by
100x^3-40x^2+4x
=4x(25x^2-10x+1)
The remaining quadratic factor is a perfect square trinomial:
25x^2-10x+1 = (5x)^2-2(5x)+1^2 = (5x-1)^2
So:
100x^3-40x^2+4x = 4x(5x-1)^2