×

# How do you factor the trinomial 12 y^2- 17y +5?

Mar 7, 2018

$\left(12 y - 5\right) \left(y - 1\right)$

#### Explanation:

$12 {y}^{2} - 17 y + 5$

multiply the coeff of ${y}^{2} \text{ & the constant}$

$12 \times 5 = 60$

find factors of $60 \text{ that add to } - 17$

$- 12 , - 5$

start by reducing the $y$ term with these factors then factorise by grouping.

$12 {y}^{2} - 12 y - 5 y + 5$

$\left(12 {y}^{2} - 12 y\right) - \left(5 y - 5\right)$

$12 y \left(y - 1\right) - 5 \left(y - 1\right)$

$\left(12 y - 5\right) \left(y - 1\right)$