How do you factor the trinomial #12 y^2- 17y +5#?

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Answer 1 · 2018-03-07T09:33:52

#(12y-5)(y-1)#

#12y^2-17y+5#

multiply the coeff of #y^2" & the constant"#

#12xx5=60#

find factors of #60" that add to "-17#

#-12,-5#

start by reducing the #y# term with these factors then factorise by grouping.

#12y^2-12y-5y+5#

#(12y^2-12y)-(5y-5)#

#12y(y-1)-5(y-1)#

#(12y-5)(y-1)#