How do you factor the trinomial $25w² - 5w - 6$ ?

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Answer 1 · 2016-06-06T09:43:50

$(5w+2)(5w-3)$

first, solve the equation $25w^2-5w-6=0$ :

$w=(5+-sqrt(5^2-4*25*(-6)))/(2*25)$

$w=(5+-sqrt(25+600))/50$

$w=(5+-25)/50$

$w=-2/5 and w=3/5$

then let's factor:

$25w^2-5w-6=25(w+2/5)(w-3/5)$

and simplify to have no fractions:

$(5w+2)(5w-3)$

How do you factor the trinomial 25w² - 5w - 625w² - 5w - 6?