How do you factor the trinomial #25w² - 5w - 6#?

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Answer 1 · 2016-06-06T09:43:50

#(5w+2)(5w-3)#

first, solve the equation #25w^2-5w-6=0#:

#w=(5+-sqrt(5^2-4*25*(-6)))/(2*25)#

#w=(5+-sqrt(25+600))/50#

#w=(5+-25)/50#

#w=-2/5 and w=3/5#

then let's factor:

#25w^2-5w-6=25(w+2/5)(w-3/5)#

and simplify to have no fractions:

#(5w+2)(5w-3)#