How do you factor the trinomial #3r ^3 -3r ^2-6r#?

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Answer 1 · 2016-03-01T04:11:59

#3r^3-3r^2-6r=color(blue)(3r(r+1)(r-2))#

#3r^3-3r^2-6r#

Factor out the GCF #3r#.

#3r(r^2-r-2)#

Factor #r^2-r-2#.

Find two numbers that when added equal #-1# and when multiplied equal #-2#. The numbers #1# and #-2# meet the requirements.

Rewrite the expression as its factors.

#3r(r+1)(r-2)#