How do you factor the trinomial #4x^2 + 20x + 25#?

1 Answer
Apr 26, 2017

#color(black)((2x+5))color(black)((2x+5))# or #(2x+5)^2#

Explanation:

#4x^2+20x+25#

I like to use the factor by grouping method when working with polynomials whose leading coefficient is not #1#.

We need to find two numbers that multiply to #100# (#4*25#) and that add to #20#:

#color(white)(..)+20#
#color(white)(..)xx100#
.......................
#color(white)(.)1xx100#
#color(white)(.)2xx50#
#color(white)(.)4xx25#
#color(white)(.)5xx20#
#color(white)()10xx10#

#10+10=20# and #10xx10=100#! It looks like we've found our two values. But, we're not done yet...

to factor by grouping, we still need to group. I'll set it up and walk you through it:
First, we take the leading value #(4x^2)# and the constant #(25)# and place them in two parentheses, jopined together with addition:
#(4x^2+ _ )+( _ +25)#
We need to leave spaces for our two numbers, #10# and #10#
Now we insert them into the blank spaces:

#(4x^2+10color(orange)(x))+(10color(orange)(x)+25)#
Note It's important to add that #x#. The system won't work without it!

Now we just factor the parenthases:
#color(red)(2x)color(blue)((2x+5))+color(red)(5)color(blue)((2x+5))#
if the two parenthases look the same, we did everyhtign right! Now comes the magic...

Our factors are #color(red)((2x+5))color(blue)((2x+5))#. That's the same thing as #(2x+5)^2#.