Question

How do you factor the trinomial `4x^2 - 9x - 9`?

Answer 1

Here's what I did:

Explanation:

`4x^2-9x-9`

To factor this, we need to find 2 numbers which:

• multiply up to `-36`
• add up to `-9`

These 2 numbers are `-12` and `3`. So now the expression looks like this:
`4x^2 - 12x + 3x - 9`

Now we can factor by grouping:
`4x(x-3) + 3(x-3)`

And the final factored format is:
`(4x+3)(x-3)`

Hope this helps!