How do you factor the trinomial #6a^2 - 66a + 168#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Binayaka C. Jul 15, 2016 #6(a-4)(a-7)# Explanation: #6a^2-66a+168=6(a^2-11a+28)=6(a^2-7a-4a+28)=6(a(a-7)-4(a-7))=6(a-4)(a-7)#[Ans] Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1297 views around the world You can reuse this answer Creative Commons License