How do you factor the trinomial #6x ^2+13x+5#?

1 Answer
George C.
Jan 17, 2016

Use an AC method, factoring by grouping to find:

#6x^2+13x+5=(2x+1)(3x+5)#

Explanation:

Look for a pair of factors of #AC = 6*5=30# with sum #B=13#.

The pair #10, 3# works:

#10xx3 = 30#

#10+3 = 13#

Then use that pair to split the middle term and factor by grouping:

#6x^2+13x+5#

#=(6x^2+10x)+(3x+5)#

#=2x(3x+5)+1(3x+5)#

#=(2x+1)(3x+5)#

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