How do you factor the trinomial #9-10x+x^2#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Sonnhard Jun 2, 2018 #(x-9)(x-1)# Explanation: Solving #x^2-10+9=0# we get #x_{1,2}=5pmsqrt(25-9)# so #x_1=9# #x=1# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1373 views around the world You can reuse this answer Creative Commons License