How do you factor the trinomial #9t^2 - 25#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Meave60 Dec 24, 2015 #9t^2-25=(3t+5)(3t-5)# Explanation: #9t^2-25# is an example of the difference of squares, #(a^2-b^2)=(a+b)(a-b)#, where #a=3t and b=5#. Rewrite. #(3t)^2-5^2# Factor. #(3t+5)(3t-5)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1966 views around the world You can reuse this answer Creative Commons License