How do you factor the trinomial #a^4 - 8a^2 + 16#?

1 Answer
Feb 16, 2016

#a^4-8a^2+16=color(green)((a-2)^2(a+2)^2)#

Explanation:

Temporarily replace #a^2# with b#

The expression becomes
#color(white)("XXX")b^2-8b+16#
which factors easily as
#color(white)("XXX")(b-4)^2#

But #(b-4) = (a^2-4)#
which can be factored as #(a+2)(a-2)#

So
#color(white)("XXX")a^4-8a^2+16=(b-4)^2#
#color(white)("XXXXXXXXXXX")= ((a+2)(a-2))^2#
#color(white)("XXXXXXXXXXX") = (a+2)^2(a-2)^2#