How do you factor the trinomial # j^2+22j+40#?

1 Answer
Feb 16, 2016

#j^2+22j+40 = color(green)((j+2)(j+20))#

Explanation:

[Note: I edited the question to make it "22j" instead of just "22"; hope this was what was intended].

#(j+a)(j+b)=j^2+(a+b)j+ab#

So in order to write #j^2+22j+40# as the product of two binomials,
we want to find values #a# and #b# such that
#a+b=22# and #axxb=40#