Question

How do you factor the trinomial `x^2 + 11x - 28`?

Answer 1

`(x+(11+sqrt(233))/2)(x-(-11+sqrt(233))/2)`

Explanation:

`x²+11x-28`
`Delta=11²-4*1*(-28)=121+112=233`
`x1=(-11-sqrt(233))/2`
`x2=(-11+sqrt(233))/2`
So a factorized form of the trinomial is : `(x-(-11-sqrt(233))/2)(x-(-11+sqrt(233))/2)`
\0/ here's our answer !