How do you factor the trinomial #x^2-12x+35#?

1 Answer
Mar 15, 2018

See a solution process below:

Explanation:

Because the #x^2# coefficient is #1# we know the coefficient for the #x# terms in the factor will also be #1#:

#(x )(x )#

Because the constant is a positive and the coefficient for the #x# term is a negative we know the sign for the constants in the factors will both be negative because a negative plus a negative is a negative and negative times a negative is a positive:

#(x - )(x - )#

Now we need to determine the factors which multiply to 35 and also add to 12:

#1 xx 35 = 35#; #1 + 35 = 36 # <- this is not the factor

#5 xx 7 = 35#; #5 + 7 = 12 # <- this IS the factor

#(x - 5)(x - 7)#