How do you factor the trinomial # x^2 + 14x + 49 #?

1 Answer
Nov 19, 2015

#(x+7)^2#

Explanation:

Suppose we have the variables 'a' and 'b' where

#ab=49#
#a+b=14#

Note that this approach only works if the coefficient of #x^2# is 1.
That is: #x^2 -= 1 times x^2color(white)(xxxxxx) ( or 1x)#

#7 times 7 =49#
#7+7 =14#

So we have:

#(x+7)(x+7) -= (x+7)^2#

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Foot note for reference:
#(x+7)(x+7) " is the same as " x(x+7) + 7(x+7)#