How do you factor the trinomial #x^2+2x-63#?

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Answer 1 · 2018-03-28T18:29:45

#x^2+2x-63=(x+9)*(x-7)#

#x^2+2x-63#

=#x^2+2x+1-64#

=#(x+1)^2-8^2#

=#(x+1+8)*(x+1-8)#

=#(x+9)*(x-7)#

Answer 2 · 2018-03-28T18:36:08

# (x +9) xx ( x -7) #

In the # Ax^2 + Bx + C#

The C term is negative this means that one binomial factor must be negative and the other positive.

The B term is positive this means that the positive binomial factor must be larger than the negative binomial factor.

The B coefficient is 2 so there must be a difference of 2 between the two binomial factors.

Factors of 63 are

63 x 1
21 x 3
9 x 7

The set of factors for 63 with a difference of 2 are 9 and 7 so
the factors of # x^2 + 2x - 63# are

( x +9) xx ( x -7)