How do you factor the trinomial #x^2-7x+6#?

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Answer 1 · 2018-03-11T13:22:17

#(x-1)(x-6)#

#"factor using the a-c method"#

#"the factors of + 6 which sum to - 7 are - 1 and - 6"#

#rArrx^2-7x+6=(x-1)(x-6)#

Answer 2 · 2018-03-11T13:24:34

#x^2-7x+6=(x-1)(x-6)#

#x^2-7x+6#

First, find two numbers that add up to #-7# and multiply to give #6#,

#-1# and #-6#, where these two numbers are roots.

Next, add #x# to the numbers,

#(x-1)# and #(x-6)#, where these two numbers are factors.

Now, factor,

#x^2-7x+6=(x-1)(x-6)#