How do you factor #w^2+4w+3#?

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Mar 7, 2018

Answer:

#(w+3)(w+1)#

Explanation:

In this case, since #a = 1# (in #ax^2+bx+c#), simply look for two numbers whose sum is #4# and whose product is #3#. You can easily see that the two numbers are #1# and #3#.

Then, just write it down: #(w+3)(w+1)#

Check: try expanding the brackets using FOIL.

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