How do you factor #-x^2 + 11x + 26#?

Question

3004 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-15T03:15:15

To make things easier, you can take the factor #-1# out:

#=-1*(x^2-11x-26)#

Now we factor #-26=-13*2#

These factors add up to #-11=# goal accomplished!

Complete factoring:

#=-(x-13)(x+2)#

We can even make the #-# disappear:

#=(13-x)(x+2)#