How do you factor #x^2+13x+12#?

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Answer 1 · 2018-05-24T19:44:56

#(x+12)(x+1)#

#"the factors of + 12 which sum to + 13 are + 12 and + 1"#

#x^2+13x+12=(x+12)(x+1)#

Answer 2 · 2018-05-24T20:12:05

#(x+12)(x+1)#

We need to think of two numbers that sum up to #13# and have a product of #12#. These will become our factors.

After some trial and error, we arrive at #12# and #1#. Thus, we have

#(x+12)(x+1)#

Hope this helps!