How do you factor # x^2-2x+1#?

1 Answer
Jul 25, 2015

This is a perfect square trinomial:

#x^2-2x+1 = (x-1)(x-1) = (x-1)^2#

Explanation:

In general, you can recognise these perfect square trinomials, because they take the form #a^2+2ab+b^2 = (a+b)^2# or #a^2-2ab+b^2 = (a-b)^2#

In this particular case, there's a little trick to help spot it:

The coefficients of your quadratic - ignoring the signs - are #1#, #2# and #1#. Does the sequence #1 2 1# ring any bells? Well #121 = 11*11 = 11^2# and #x^2-2x+1 = (x-1)^2#, where the coefficients of #x-1# - ignoring signs - are #1# and #1#.

This works with a few other trinomials, like:

#x^2+6x+9 = (x+3)^2# like #169 = 13^2#

It only works if the numbers are small enough, but it can help.