Question

How do you factor `x^2-3x-10`?

Answer 1

`x^2-3x-10 = (x-5)(x+2)`

Explanation:

Given:

`x^2-3x-10`

Find a pair of factors of `10` which differ by `3`.

The pair `5, 2` works in that `5*2=10` and `5-2=3`

Hence we find:

`x^2-3x-10 = (x-5)(x+2)`