Question

How do you factor `x^2-3x-28=0`?

Answer 1

`(x-7)(x+4) = 0`

Explanation:

Look for a pair of factors of `28` which differ by `3`

The pair `7, 4` works in that `7*4=28` and `7-4=3`

Hence:

`0 = x^2-3x-28 = (x-7)(x+4)`