How do you factor $x^{2} - 4 x + 3$ $x^2-4x+3$ ?

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How do you factor $x^{2} - 4 x + 3$ $x^2-4x+3$ ?

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Answer 1 · 2016-06-04T22:16:14

x=1, 3

Explanation:

you start by finding a number that multiplies to 3 and adds to -4. they will both be negative as the product is positive and the sum negative. your numbers are -1 and -3. split up the 4x so that you can factor the equation further.

$x^{2} - 4 x + 3$ $x^2-4x+3$

$x^{2} - x - 3 x + 3$ $x^2-x-3x+3$

$x (x - 1) - 3 (x - 1)$ $x(x-1)-3(x-1)$

$(x - 3) (x - 1)$ $(x-3)(x-1)$

$x = 3$ $x=3$ or $1$ $1$

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How do you factor $x^{2} - 4 x + 3$ $x^2-4x+3$ ?

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