How do you factor #x^2 - 4x + 4 =0#?

1 Answer
EZ as pi
Jul 27, 2016

#(x-2)(x-2) = 0#
#x = 2#

Explanation:

To factor the expression you need to find factors of 4 which add up to 4.

The signs will be the same (because of +4), they are both minus (because of -4x).

#2 xx2 = 4 and 2 + 2 = 4#

#(x-2)(x-2) = 0#

Now that we have the factors, we can solve:
If #x - 2 =0", then "x =2#

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