How do you factor x^3-18x^2+81x? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer George C. Jun 14, 2015 Separate the common x factor then recognise remaining the perfect square trinomial to find: x^3-18x^2+81x = x(x-9)^2 Explanation: x^3-18x^2+81x = x(x^2-18x+81) We can recognise x^2-18x+81 as being a perfect square trinomial, as it is of the form a^2-2ab+b^2 = (a-b)^2 with a=x and b=9. Thus: x^3-18x^2+81x = x(x^2-18x+81) = x(x^2-(2*x*9)+9^2) = x(x-9)^2 Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor x^2+16x+48? How do you factor x^2-9x+20? Question #3fdac How do you factor 8+z^6? There is no GCF to be factor out, so is there another method to complete this? How do you factor 2t^2+7t+3? See all questions in Factorization of Quadratic Expressions Impact of this question 3315 views around the world You can reuse this answer Creative Commons License