How do you factor #x^6 - y^6#? Algebra Polynomials and Factoring Special Products of Polynomials 1 Answer Harish Chandra Rajpoot Jul 9, 2018 #x^6-y^6=(x-y)(x+y)(x^4+y^4+x^2y^2)# Explanation: #x^6-y^6# #=(x^2)^3-(y^2)^3# #=(x^2-y^2)((x^2)^2+(y^2)^2+(x^2)(y^2))# #=(x^2-y^2)(x^4+y^4+x^2y^2)# #=(x-y)(x+y)(x^4+y^4+x^2y^2)# Answer link Related questions What are the Special Products of Polynomials? What is a perfect square binomial and how do you find the product? How do you simplify by multiplying #(x+10)^2#? How do you use the special product for squaring binomials to multiply #(1/4t+2 )^2#? How do you use the special product of a sum and difference to multiply #(3x^2+2)(3x^2-2)#? How do you evaluate #56^2# using special products? How do you multiply #(3x-2y)^2#? How do you factor # -8x^2 +32#? How do you factor #x^3-8y^3#? How do you factor # x^3 - 1#? See all questions in Special Products of Polynomials Impact of this question 36229 views around the world You can reuse this answer Creative Commons License