How do you find $_{11} P_{3}$ $""_11P_3$ ?

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Answer 1 · 2017-06-02T19:41:24

$_{11} P_{3} = 990$ $"_11P_3=990$

$_{n} P_{r} = \frac{n!}{(n - r)!}$ $"_nP_r=(n!)/((n-r)!)$

$_{11} P_{3} = \frac{11!}{(11 - 3)!}$ $"_11P_3=(11!)/((11-3)!)$

$"_11P_3=(11xx10xx9xxcancel(8!))/cancel((8!))$

$"_11P_3=990$

How do you find ""_11P_311P3""_11P_3?