How do you find 2p(a) + p(a-1) for the function #p(x)= x^2 - 5x + 8#?

1 Answer
Jun 1, 2016

#3a^2-17a+30#

Explanation:

If
#color(white)("XXX")p(color(red)(x))=color(red)(x)^2-5color(red)(x)+8#
then
#color(white)("XXX")p(color(red)(a))=color(red)(a)^2-5color(red)(a)+8#
and
#color(white)("XXX")2p(color(red)(a))=2color(red)(a)^2-10color(red)(a)+16#
and
#color(white)("XXX")p(color(red)(a-1))=color(red)(""(a-1))^2-5color(red)(""(a-1))+8#
#color(white)("XXXXXXX")=a^2-2a+1-5a+5+8#
#color(white)("XXXXXXX")=a^2-7a+14#

So
#2p(a)+p(a-1)#

#color(white)("XXX")=2a^2-10a+16#
#color(white)("XXXX")+underline(color(white)("x")a^2-7a+14)#
#color(white)("XXX")=3a^2-17a+30#