How do you find a=1/3(2b-5c) given b=<6,3> and c=<-4,8>?

1 Answer
Aug 21, 2017

#ula=((32/3),(-34/3))#

Explanation:

#ula=1/3(2ulb-5ulc)#

#color(white)(xx)=1/3[2((6),(3))-5((-4),(8))]#

#"multiply each component by the scalar quantity"#

#ula=1/3[((12),(6))+((20),(-40))]#

#"add corresponding components in each vector"#

#rArrula=1/3((32),(-34))=((32/3),(-34/3))#