# How do you find a numerical value of one trigonometric function of x given 1/cotx-secx/cscx=cosx?

Nov 12, 2016

$x = \pm \frac{\pi}{2} + \pi n$

#### Explanation:

$\frac{1}{\cot} x - \sec \frac{x}{\csc} x = \cos x$

$\tan x - \tan x = \cos x$

$0 = \cos x$

${\cos}^{-} 1 0 = x$

$x = \pm \frac{\pi}{2} + \pi n$