# How do you find a polynomial function of degree 4 with -1 as a zero of multiplicity 3 and 0 as a zero of multiplicity 1?

Jun 6, 2015

Just multiply:

${\left(x + 1\right)}^{3} \cdot \left(x - 0\right)$

$= \left({x}^{3} + 3 {x}^{2} + 3 x + 1\right) x$

$= {x}^{4} + 3 {x}^{3} + 3 {x}^{2} + x$