How do you find a polynomial function that has zeros #x=0, sqrt3, -sqrt3# and degree n=3?

1 Answer
Sep 13, 2017

Answer:

#p(x)=x^3-3x#

Explanation:

#"since the zeros are "x=0,x=sqrt3,x=-sqrt3" then"#

#"the factors are "x,(x-sqrt3),(x+sqrt3)#

#"the polynomial is then the product of the factors"#

#rArrp(x)=x(x-sqrt3)(x+sqrt3)#

#color(white)(rArrp(x))=x(x^2-3)#

#color(white)(rArrp(x))=x^3-3xlarr" is a possible polynomial"#