# How do you find a polynomial function with Degree: 6, Leading coefficient: 4, zeros: 3, 0 (multiplicity 3), and 2-3i?

$4 {x}^{3} \left(x - 3\right) \left({\left(x - 2\right)}^{2} + 9\right) = 4 \left({x}^{6} - 7 {x}^{5} - {x}^{4} + 39 {x}^{3}\right)$
The polynomial is $4 {x}^{3} \left(x - 3\right) \left(x - \left(2 = 3 i\right)\right) \left(x + \left(2 - 3 i\right)\right)$ = $4 {x}^{3} \left(x - 3\right) \left({\left(x - 2\right)}^{2} + 9\right)$