How do you find a polynomial function with zeroes 3,-2,1?

1 Answer
Oct 20, 2015

Answer:

The polynomial is: #x^3-2x^2-5x+6#

Explanation:

When a number #a# is a zero of a polynomial, then this polynomial is divisible by #(x-a)#, so to find the polynomial with zeros #-2,1,3# you have to multiply #(x+2)(x-1)(x-3)#

#(x+2)(x-1)(x-3)=(x^2+x-2)*(x-3)=x^3+x^2-2x-3x^2-3x+6=x^3-2x^2-5x+6#