How do you find a power series representation for # (10x)/(14+x) # and what is the radius of convergence?

1 Answer
Oct 8, 2015

#10( x/14 -(x/14)^2 +(x/14)^3-......oo)#

Radius of convergence 14

Explanation:

#(10x)/(14+x)= 10(x/(14+x))#

=#10(1- 14/(14+x))#

=#10 - 10(1/(1+x/14))#

Now comparing with the geometric power series #1/(1-x)= 1 +x +x^2 ....oo# and writing #-x/14# for x, the series would be,

#10-10(1-(x/14) +(x/14)^2 -(x/14)^3 +.....oo)#

#=10( x/14 -(x/14)^2 +(x/14)^3-......oo)#

The implied condition of a convergent geometric series represented by #1/(1-x)# is -1< x <1, hence in the present case it would be -1< -x/14 <1 0r -14 < -x <14 Or 14> x >-14. Thus the radius of convergence is 14