Question

How do you find a standard form equation for the line (0,2) (1,-2)?

Answer 1

4x + y = 2

Explanation:

Your first step in this process is to find the slope.
`(y_"2"-y_"1")/(x_"2"-x_"1")` = `(-2-2)/(1-0)`

This gives you a slope of `-4/1`

Your second step is to plug it into the point slope form with one of the points you were given.
`(y-y_"1")=m(x-x_"1")` = `(y-2)=-4/1(x-0)`

Your third step is to simplify that into your standard form which is `Ax+Bx=C`
`1(y-2) = 1[ -4(x-0)]`
`y-2=-4x+0` Distribute
`y-2+4x=0` Move the `x` value to the other side with inverse operations.
`y+4x=2` Move the `C` value to the other side with inverse operations.
`4x+y=2` Rearrange accordingly to get into the `Ax + By=C` formula.