How do you find a standard form equation for the line with (−1, −3); perpendicular to the line 2x + 7y + 5 = 0?
The slope of the given equation graphs out to be
#2x + 7y +5 = 0#
#y = -2/7x - 5/7#
The slope of the perpendicular line is the negative reciprocal of this slope
#m = - 1/(-2/7) = 7/2#
Next, you would substitute the given points and the slope that you found into the point-slope formula:
#(y - y_1) = m(x - x_1)#