How do you find a standard form equation for the line with (3,1), with slope of m=1/3?

2 Answers
Apr 16, 2018

#x-3y=0#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B,C are integers"#

#"we can obtain the equation in "color(blue)"point-slope form"#

#•color(white)(x)y-y_1=m(x-x_1)#

#"where m is the slope and "(x_1,y_1)" a point on the line"#

#"here "m=1/3" and "(x_1,y_1)=(3,1)#

#rArry-1=1/3(x-3)larrcolor(blue)"in point-slope form"#

#rArry-1=1/3x-1larrcolor(blue)"distributing"#

#rArry=1/3x#

#"multiply through by 3"#

#rArr3y=xrArrx-3y=0larrcolor(red)"in standard form"#

Apr 16, 2018

#y=1/3x#

Explanation:

The standard equation is #y=mx+c#

So we have #y=1/3x+c# and it passes through (3,1)

#1=1/3xx3+c# #=># #1=1+c# so c=0