# How do you find a standard form equation for the line with m = -6, passing through (0, -8)?

The equation of the line is $y = - 6 x - 8$
Let the equation of the line is $y = m x + c$. Here m= -6; :.y= -6x +c. The point (0,-8) satisfy the equation as it is on the liine $\therefore - 8 = - 6 \cdot 0 + c \mathmr{and} c = - 8$Hence the equation of the line is $y = - 6 x - 8$[Ans]