# How do you find a standard form equation for the line with point (2, 5) and is perpendicular to the line 4x + 9y − 7?

##### 1 Answer

Sep 30, 2017

9x - 4y + 2 = 0

#### Explanation:

Given line is 4x + 9y - 7 = 0.

or, 9y = - 4x + 7

or, y = - 4x/9 + 7/9 . It's slope is - 4/9.

Let m be the slope of the perpendicular line.

Then, m x ( - 4/9 ) = - 1

Hence m = 9/4

Let the required equation be y = 9/4 x + c. Since it passes through

(2 , 5), we get c = 5 - 9/2 = 1/2.

The equation is y = 9/4 x + 1/2

or, 4y = 9x + 2

or, 9x - 4y + 2 = 0