How do you find a standard form equation for the line with point (9, -9) and is parallel to the line 7x-9y+5 = 0?

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Answer 1 · 2016-07-28T20:44:04

#y=7/9x-16#

Rewrite the given equation as:

#y_1=7/9x_1+5/9#

The gradient being #+7/9# so any line parallel to this will have the same gradient.

Thus for the new line we have: #y_2=7/9x_2+c#.....................Equation(1)

Given that a point on this line is:#" "P_1->(x_2,y_2)=(9,-9)#

Thus by substituting #P_1# into Equation(1) we have:
#-9=7/(cancel(9))(cancel(9))+c#

#=>c=-9-7=-16#

Giving:#" "y_2=7/9x_2-16#