How do you find a third degree polynomial given roots 6 and 3-2i?
1 Answer
Jul 12, 2017
Explanation:
"note that"
"complex roots occur in conjugate pairs"
3-2i" is a root " rArr3+2i" is also a root"
rArrf(x)=(x-6)(x-(3-2i))(x-(3+2i))
color(white)(rArrf(x))=(x-6)((x-3)+2i))((x-3)-2i))
color(white)(rArrf(x))=(x-6)((x-3)^2-4i^2)
color(white)(rArrf(x))=(x-6)(x^2-6x+13)
color(white)(rArrf(x))=x^3-12x^2+49x-78