# How do you find abs( 1- i sqrt3)?

$| 1 - i \sqrt{3} | = 2$
$| a + i b | = \sqrt{{a}^{2} + {b}^{2}}$
Hence $| 1 - i \sqrt{3} | = \sqrt{{1}^{2} + {\left(- \sqrt{3}\right)}^{2}} = \sqrt{1 + 3} = \sqrt{4} = 2$