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How do you find $abs( 1- i sqrt3)$ ?

1 Answer

Shwetank Mauria

May 1, 2016

$|1-isqrt3|=2$

Explanation:

$|a+ib|=sqrt(a^2+b^2)$

Hence $|1-isqrt3|=sqrt(1^2+(-sqrt3)^2)=sqrt(1+3)=sqrt4=2$

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