How do you find $abs( -18/7 + sqrt5/7 i )$ ?

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Answer 1 · 2016-03-26T19:44:12

$|-18/7+sqrt5/7i|=sqrt(324/49+5/49)=sqrt(47/7)$

For general complex number $z=x+iy$ in rectangular form, the modulus is given by $|z|=sqrt(x^2+y^2)$ .

So in this particular case we get

$|-18/7+sqrt5/7i|=sqrt(324/49+5/49)=sqrt(47/7)$

How do you find abs( -18/7 + sqrt5/7 i )abs( -18/7 + sqrt5/7 i )?